y=-1;
if(x!=0)
if(x>0)y=1;else y=0;
所表示的数学函数关系是_______。
A.
B.
C.
D.
[单选题]与“y=(x>0?1:x0)y=1; else if(x0)y=1; else if(xO)y=1; else if(x=-0)y=0; else y=-l;D.y=0; if(x>=0) if(x>=0)y=1; else y=-l;
[单选题]与y=(x>0? 1:x0)y=1 else if(x<0)y=£1; else y=O;B.i与y=(x>0? 1:x<0? -1:0);的功能相同的if语句是A.if(x>0)y=1 else if(x<0)y=-1; else y=O;B.if(x) if(x>0)y=1; else if(x<0)y=-1;C.y=-1; if(x) if(x>0)y=1; else if(x==0)y=0; else y=-1;D.y=0; if(x>=0) if(x>0)y=1; else y=-1
[单选题]阅读下述程序段:y=-1;if(x!=0)if(x>0)y=1;elsey=0;该程序段所描述的数学关系是( )。A.B.C.D.
[单选题]下面的程序 main() { int x=3,y=0,z=0; if(x=y+z)printf("***"); else printf("####"); } _______。A.有语法错误不能通过编译B.输出****C.可以通过编译,但是不能通过连接,因而不能运行D.输出####
[单选题]有以下程序 int f1 (int x,inty){return x>y?x:y;} int f2(int x,int y){return x>y?y:x;} main() { int a=4,b=3,c=5,d=2,e,f,g; e=f2(f1(a,b),f1(c,d));f=f1(f2(a,b),f2(c,d)); g=a+b+c+d-e-f; pintf("%d,%d,%d/n",e,f,g); } 程序运行后的输出结果是 ______。A.4,3,7B.3,4,7C.52,7D.2,
[单选题]有以下程序A: int f1(int x,int y) { return x>y?x:y; } int f2(int x,int y) { return x>y?y:x; ) main() { int a=4,b=3,c=5,d=2,e,f,g; e=f2(f1(a,B),f1(c,D));f=f1(f2(a,B),f2(c,D)); g=a+b+c+d-e-f; printf("%d,%d,%d/n",e,f,g); } 程序运行后的输出结果是( )。A.4,3,7B.3,4,7C.5,2
[单选题]有以下程序int f1(int x,int y){ return x>y? x:y;}int f2(int x,int y){ return x>y? y:x;}main( ){ int a=4,b=3,c=5,d,e,f;d=f1(a,b);d=f1(d,c);e=f2(a,b);e=f2(e,c);f=a+b+c-d-e;cout<<d<<","<<f<<","<<e<<endl;}执行后输出结果是A.3,4,5B.5,3,4C.5,4,3D.3,5,4
[单选题]有以下程序: int f1(int x, int y){ return x>y? x:y; } int f2(int x, int y){ return x>y? y:x; } main() { int a=4, b=3, c=5, d=2, e, f, g; e=f2(f1(a, b), f1(c, d)); f=f1(f2(a, b) , f2(c, d)); g=a+b+c+d-e-f; printf("% d, %d, %d/n", e, f, g); } 程序运行后的输出结果是__
[单选题]有以下程序int f1(int x, int y){ return x>y? x:y;}int f2(int x, int y){ return x>y? y:x;}main(){ int a=4,b=3,c=5,d,e,f; d=f1(a,B) ;d=f1(d,C) ; e=f2(a,B) ;e=f2(e,C) ; f=a+b+c-d-e; cout<<d<<", "<<f<<", "<<e<<end1;}执行后输出结果是A.3,4,5B.5,3,4C.5,4,3D.3,5,4
[单选题]有以下程序: int f1(int x,int y) { return x>y?x:y; } int f2(int x,int y) { return x>y?y:x; } main() { int a=4,b=3,c=5,d,e,f; d=fl(a,b);d=f1(d,c); e=f2(a,b);e=f2(e,c); f=a+b+c-d-e; printf("%d,%d,%d/n",d,f,e); } 执行后输出结果是( )。A.3,4,5B.5,3,4C.5,4,3D.3,5,4