1~9放到3*3的格子里,要求横竖斜的和都相等,要能打印出结果. 用程序实现,最好思路和程序都能给  我的思路是1.求出平均值15. 2.求出4个角的数字2,4,6,8. 3.写到一个数组里. 4.打印. 我已经写了一些了,很明显我的代码不是一个成熟的程序员写的代码,并且最后向数组里放值的操作没有实现. 有没有高手有好的思路,并且写一个象样的代码.先谢谢. 写好了回加分的. 下面是我的代码,简直不成样子.见笑: package test; import java.util.A
rrayList; import java.util.A
rrays; import java.util.List; public class Test3$3 { static int count = 0; public static void main(String[] args) { // int int1=0,int2=0,int3=0,int4=0,int5=0,int6=0,int7=0,int8=0,int9=0; int[] intX = new int[9]; for (int i = 0; i < 9; i++) { intX[i] = 0; } int[] an = new int[9]; for (int i = 0; i < 9; i++) { oan[i] = i + 1; } // 每行的和 int temp = 0; for (int i = 0; i < 9; i++) { temp += oan[i]; } count = temp / 3; System.out.println(count); // List list = new A
rrayList(); for (int i = 0; i < 9 - 2; i++) { for (int j = i + 1; j < 9 - 1; j++) { for (int k = j + 1; k < 9; k++) { if (oan[i] + oan[j] + oan[k] == count) { int[] inttemp = { oan[i], oan[j], oan[k] }; // list.add(inttemp.toString()); for (int h = 0; h < 3; h++) { int inttemp1 = inttemp[h]; switch (inttemp1) { case 1: intX[0] += 1; break; case 2: intX[1] += 1; break; case 3: intX[2] += 1; break; case 4: intX[3] += 1; break; case 5: intX[4] += 1; break; case 6: intX[5] += 1; break; case 7: intX[6] += 1; break; case 8: intX[7] += 1; break; case 9: intX[8] += 1; break; default: break; } } } } } } //排序 A
rrays.sort(intX); // test for (int i = 0; i < intX.length; i++) { System.out.println(intX[i]); } // int a = intX[7];   int [][]reInt = new int[3][]; reInt [1][1] = intX[8]; }

JAVA里的九宫格怎么写?