*((int *)pval)£¯=2; £¯£¯我想问一下,这个语法怎么理解,太复杂了 具体代码如下。

#include "stdio.h"void half(void *pval,char type);main(){ int i=20; long l=100000; float ff=12.456; double d=123.044444; printf("%d/n",i); printf("%ld/n",l); printf("%f/n",ff); printf("%lf/n",d); half(&i,'i'); half(&l,'l'); half(&ff,'ff'); half(&d,'d'); printf("/n%d",i); printf("/n%ld",l); printf("/n%f",ff); printf("/n%lf",d); return 0; }void half(void *pval,char type){ switch(type) { case 'i': { *((int *)pval)/=2; //我想问一下，这个语法怎么理解，太复杂了 break; } case 'l': { *((long *)pval)/=2; break; } case 'ff': { *((float *)pval)/=2; break; } case 'd': { *((double *)pval)/=2; break; } } }