struct stu
{int num;
charname[20];
}x[5]={1,"LI",2,"ZHAO",3,"WANG",4,"ZHANG",5,"LIU"};
for(i=1;i<5;i++)
printf("%d%C",x[i].num,x[i]name[2]);
以上程序段的输出结果为( )。
A.2A3N4A5U
B.112A3H41
C.1A2N3A4U
D.2H3A4H51
[单选题]定义结构体数组:struct stu{ int num;char name[20];}x[5]={1,"LI",2,"ZHAO",3,"WANG",4,"ZHANG",5,"LIU"};for(i=1;i<5;i++)printf("%d%c",x[i].num,x[i].name[2];以上程序段的输出结果为( )。A.2A3N4A5UB.112A3H41C.1A2N3A4UD.2H3A4H51
[单选题]定义结构体数组 struct stu { int num; char name[20]; }x[5]={1,"ZHAO",2,"QIAN",3,"SUN",4,"LEE",5,"ZHOU"}; for(i=1;i<5;i++) printf("%d%c",x[i].num,x[i].name[2]); 程序执行后的输出结果是( )。A.2A3N4E5OB.1H2I3U4EC.1A2N3E4OD.1A2N3E4O
[单选题]定义结构体数组: struct stu { int num; char name[20]; }x[5]={1,"LI",2,"ZHAO",3"WANG",4,"ZHANG",5"LIU"}; for(i=1;i<5;i++) printf("%d %c", x[i].num, x[i].name[2]); 以上程序段的输出结果为( ).A.2A3N4A5UB.1I2a3h4IC.1A2N3A4UD.2H3A4H5I
[单选题]定义结构体数组: struct stu { int num; char name[20]; }x[5];{1,"L1",2,"ZHAO",3,"WANG",4,"ZHANG",5,"LIU"}; for(i=1;i<5;i++) printf("%d%c",x[i].num,x[i].name[2]); 以上程序段的输出结果为( )。A.2A3N4A5UB.1I2A3H4IC.1A2N3A4UD.2H3A4H5I
[单选题]若有结构体定义: struct stu{int num; char sex; int age; }a1,a2; 则下列语句中错误的是( )。A.printf("%d,%c,%d",a1);B.a2.age=a1.age;C.a1.age++;D.a1.num=5;
[单选题]若有结构体定义:struct stu {int num;char sex;int age;}a1,a2;则下列语句中错误的是( )。A.printf("%d%c,%d",a1);B.a2.age=a1.age;C.a1.age++;D.a1.num=5;
[单选题]若有结构体定义:struct stu{int num;char sex;int age;}al,a2;则下列语句中错误的是( )。A.printf("%d,%C,%d",a1);B.a2.age=a1.age;C.a1.age++;D.a1.num=5;
[单选题]有以下程序: include struct STU {int num; float TotalScore;有以下程序: #include <strino.h> struct STU {int num; float TotalScore; }; void f(struct STU p) {struct STU s[2]={{20044,550},{20045,537}}; p.num=s[1].num;p.TotalScore=s[1].TotalScore; } main() {struct
[单选题]有以下程序: struct STU {char name[10];int num;float TotalScore;}; void f(struct STU *p) {struct STU s[2]={{"SunDan",20044,550},{"Penghua",20045,537}},*q=s; ++p;++q; *p=*q; } main() {struct STU s[3]={{"YangSan",20041,703},{"LiSiGuo",20042,580}}; f(
[单选题]有以下程序 struct STU { char name[10]; int num; int Score; { main() { struct Stu s[5]={{"YangSan",20041,703},{"LiSiGuo",20042,580}, {"WangYin",20043,680},{"SunDan",20044,550}, {"Penghua",20045;537}},*p[5],*t; int i,j; for(i=0;i<5;i++)p[i]=&s