下面程序的输出结果是（）。#include<stdio.h>main(){ int a[4][5]={1,2,4,-4,5,-9,3,6,-3,2,7,8,4};int i,j,n;n=9;i=n/5;j=n-i*5-1;printf("a[%d][%d]=%d/n",i,j,a[i][j]); } 执行后输出结果是（ ）。A）a[1][3]=6 B）a[1][3]=-3C）a[1][3]=2 D）不确定

[单选题]下面程序的输出结果是#include<stdio.h>main(){ int a[]={1,2,3,4,5,6,7,8,9,0},*p;p=a;printf("%d/n",*p+9);}A．0B．1C．10D．9

[单选题]下面程序的输出结果是#include<stdio.h>main(){ int a[]={1,2,3,4,5,6,7,8,9,0},*p;p=a;printf("%d/n",*p+9);}A．0B．1C．10D．9

[单选题]下面程序的输出结果是#include<stdio.h>#include<string.h>main(){ char *p1="abc",*p2="ABC",str[50]= "xyz";strcpy(str+2,strcat(p1,p2));printf("%s/n",str);}A．xyzabcABCB．zabcABCC．xyabcABCD．yzabcABC

[试题]以下程序的输出结果是 ( 8 ) 。#include<stdio.h>main(){int i,j,sum;for(i=3;i>=1;i--){sum=0;for(j=1;j<=i;j++) sum+=i*j;}printf("%d/n",sum);}

[试题]以下程序的输出结果是 ( 9 ) 。#include<stdio.h>main(){ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;for(j=3;j;j--){ switch(j){ case 1:case 2:printf( " %d " ,*p++); break;case 3:printf( " %d " ,*(--p));}}}

[单选题]以下程序的输出结果是#include<stdio.h>main(){int a=15,b=21,m=0;switch(a%3){case 0:m++;break;case 1:m++;switch(b%2){ default:m++;case 0:m++;break; } }printf("%d/n",m);}A．1B．2C．3D．4

[单选题]如下程序的输出结果是#include<stdio.h>main(){ char ch[2][5]={"6937","8254"},*p[2];int i,j,s=0;for(i=0;i<2;i++) p[i]=ch[i];for(i=0;i<2;i++)for(j=0;p[i][j]>′/0′;j+=2)s=10*s+p[i][j]-′0′;printf("%d/n",s);}A．69825B．63825C．6385D．693825

[单选题]如下程序的输出结果是#include<stdio.h>main(){ char ch[2][5]={"6937","8254"},*p[2];int i,j,s=0;for(i=0;i<2;i++) p[i]=ch[i];for(i=0;i<2;i++)for(j=0;p[i][j]>′/0′;j+=2)s=10*s+p[i][j]-′0′;printf("%d/n",s);}A．69825B．63825C．6385D．693825

[单选题]下述程序的输出结果是#include<stdio.h>void main(){ int a[5]={2,4,6,8,10};int *p=a,**q=&p;printf("%d,",*(p++));printf("%d",**q); }A．4,4B．2,2C．4,5D．2,4

[单选题]下述程序的输出结果是#include<stdio.h>void main(){ int a[5]={2,4,6,8,10};int *p=a,**q=&p;printf("%d,",*(p++));printf("%d",**q); }A．4,4B．2,2C．4,5D．2,4