A.30
B.15
C.20
D.10
[单选题]现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0||k[i]%5==0)count++;i++; }printf("%d,%d/n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
[单选题]现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0||k[i]%5==0)count++;i++; }printf("%d,%d/n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
[单选题]现有如下程序段#include "stdio.h"main( ){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段#include "stdio.h"main(){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段#include "stdio.h"main(){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]有如下程序段#include "stdio.h"main(){ int k[10]; int j; for(j=0;j<10;j++) scanf("%d",&k[j]); for(j=9;j> =0;j--) printf("%d",k[j]);}则程序段实现的功能是A.输入10个数据的顺序输入并输出 B.输入10个数据的逆序存放C.输入10个数据的逆序输出D.以上叙述均错误
[单选题]有如下程序#include "stdio.h"main(){ int j,i,k=0; for(j=20;j<=30;j++) { if(!(k%10))printf("\n"); for(i=2;i<j;i++)if(!(j%i))break; if(i>=j-1) { printf("%d",j); k++;} }}程序的运行结果是A.2329 B.2923C.3292 D.9232
[单选题]有如下程序#include "stdio.h"fun(int a,int b){ int s; s=a*(b/4); printf("%d\n",s);}main(){ int a=16,b=10; fun(a,b);}该程序的输出结果是A.16 B.32C.40 D.80
[单选题]现有如下程序段 #include"stdio.h" main() { int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21, 1}; int i=0,j=5; printf("%d/n",*(&a[0][0]+2*i+j-2));} 则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段 #include "stdio.h" main() { int k[30]={12,324,45,6,768,98,21,34,453,456}; int count=0,i=0; while(L[i]) { if(k[i]%2==0||k[i]%5==0)count++; i++; } printf("%d,%d/n",count,i);} 则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10