A.69825
B.63825
C.6385
D.693825
[单选题]有如下程序: main() {char ch[2][5]={"6937","8254"},*p[2]; int i,j,S=0; for(i=0;i<2;i++) p[i]=ch[i]; for(i=0;i<2;i++) for(j=0;p[i][j]>'/0';j+=2) s=10*s+p[i][j]-'0'; printf("%d/n",S); } 该程序的输出结果是( )。A.69825B.63825C.693825D.6385
[单选题]有如下程序 main() { char ch[2][5]={"6937","8254"},*p[2]; int i,j,s=0; for(i=0;i<2;i++) p[i]=ch[i]; for(i=0;i<2;i++) for(j=0;p[i][j]>'/0';j+=2) s=10*s+(p[i][j]-'0'); printf("%d/n",s); } 该程序的输出结果是_____。A.69825B.63825C.6385D.693825
[单选题]有如下程序 main() { char ch[2][5]={"6937","8254"},*p[2]; int i,j,s=0; for(i=0;i<2;++)p[i]=ch[i]; for(i=0;i<2;i++) for(j=0;p[i][j]>'/0';j+=2) s=10*s+p[i][j]-'0'; printf("%d/n",s);} 该程序的输出结果是A.69825B.63825C.6385D.693825
[单选题]有如下程序 main() { char ch[2][5]={"6937","8254"},*p[2]; int i,j,s=0; for(i=0;i<2;i++)p[i]=ch[i]; for(i=0;i<2;i++) for(j=0;p[i][j]>'/0'; j+=2) s=10*s+p[i][j]-'0'; printf("%d/n",s);} 该程序的输出结果是A.69825B.63825C.6385D.693825
[单选题]有如下程序main(){ char ch[2][5]={"6937","8254"},*p[2];int i,j,s=0;for(i=0;i<2;i++)p[i]=ch[i];for(i=0;i<2;i++)for(j=0;p[i][j]>′/0′;j+=2)s=10*s+p[i][j]-′0′;printf("%d/n",s);}该程序的输出结果是A.69825B.63825C.6385D.693825
[单选题]有如下程序main(){ char ch[2][5]={"6937","8254"},*p[2];int i,j,s=0;for(i=0;i<2;i++)p[i]=ch[i];for(i=0;i<2;i++)for(j=0;p[i][j]>′/0′;j+=2)s=10*s+p[i][j]-′0′;printf("%d/n",s);}该程序的输出结果是A.69825B.63825C.6385D.693825
[单选题]有如下程序: main() {char ch[2][5]={"6937","8254"},*p[2]; int i,j,s=0; for(i=0;i<2;i++)p[i]=ch[i]; for(i=0;i<2;i++) for(j=0;p[i][j]!='/O';j+=2) s=10*s+p[i][j]-'0'; printf("%d/n",s);} 该程序的输出结果是______。A.69825B.63825C.6385D.693825
[单选题]有如下程序main(){char ch[2][5]={"6937","8254"},*p[2];int i,j,s=0;for(i=0;i<2;i++)p[i]=ch[i];for(i=0;i<2;i++)for(j=0;p[i][j]>′\0′;j+=2)s=10*s+p[i][j]-′0′;printf("%d\n",s);}该程序的输出结果是A.69825B.63825C.6385D.693825
[单选题]有如下程序:includevoid main( ){char ch[2] [5] ={"6937","8254"},* p[2] ;int i,有如下程序: #include<iostream.h> void main( ) { char ch[2] [5] ={"6937","8254"},* p[2] ; int i,j,s=0; for(i=0;i<2;i++) p[i] =ch[i] ; for(i=0;i<2;i++) for(j=0;p[i] [j] >'/0';
[单选题]有如下程序includevoid main(){char ch[2][5]=={"6937","8254"},*p[2];int i,j,s=0有如下程序 #include<iostream.h> void main() {char ch[2][5]=={"6937","8254"},*p[2]; int i,j,s=0; for(i=0;i(2;i++)p[i]=ch[i]; for(i=0;i(2;i++) for(j=0;p[i][j]>'/0,j+=2) s=10*s+